How can we produce pointed arch parametric ?
Hi Everyone all of us Know the usage of pointed arch especially in religion buildings. The forum covered the arch (curve one) What about arch one?
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Is this more Gothic or Islamic in design?Developer at Anguleris BIMsmith Marketplace.
Previously at Sumex Design for ARCAT.com -
Islamic especially second one.Comment
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If both A, H & R are controlled by manual input, you can construct it with simple ref. planes and ref. lines.
And having done that already, it would be simple to throw in some formulas for equilateral archs etc.
Example of equilateral arch:
A = R
H = A * sin(60°)
Note: If you only need a equilateral arch, it'll be much simpler to just layout a equilateral triangle, and use that for the base.Klaus Munkholm
"Do. Or do not. There is no try."Comment
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Munkholm thanks , i do not see in the attached file you used any formulas and it is parametric which seems great. (curve one can be done like that without need to formulas ??:ka: i hope )Originally posted by Munkholm View Post
so is this formula to make half of arch is equal to the another half arch.Comment
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No, the above formula would be for fitting the pointed arch on to a equilateral triangle (Which, as noted above, could be done easier without the formula)Originally posted by ahmed_hassan View Post
The formulas aren't needed at all, the only reason I mention them, is that geometry like that is often based on some rules of thumb. Like "The Height should equal 1½ times the Width" (Or whatever...)
Formulas could also be used to ensure that the family don't break with certain values (The above family will break at certain conditions - Like if the radius is to small)Klaus Munkholm
"Do. Or do not. There is no try."Comment
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