you cannot have an array to a sole object, the minimum objects for an array is set to 2, so it may be your problem, HTH

Thanks for your Reply Andres,

I understand that you can not have an array to a sole object, but thats what i want to keep the array at 2 when lenght is < 1000mm to prevent the error, and turn off the Array (visibility) in combination of turning on the second family (sole object).

But i can't make it happen, don't know how to write the formula.

There are tricks for this.
What you need to do is add a new parameter that holds the actual amount of rozetten (aantal_calc). This should then have a formula, something like IF (aantal < 2, 2, aantal). This means that if the value is smaller then 2 it still takes 2 as the value. This solves the array of 1 issue. BUT you still have an array of 2 left.

So next step is to add a visibility parameter to the array that hides it when the value of 'aantal' is less then 2.

Next step is to add one of the rozetten on top of the first one of your array and add visibility parameter to it that hides it when the value of 'aantal' is greater then 1.


What this all means is that the array will be shown when you value of 'aantal' is 2 or heigher and that the single rozet will be shown when the value of 'aantal' is less then 2.

To make it easier I would add the array to a nested family, that way you can hide the entire family all at once.


oh and of course the most important bit, Welcome to the forum !

Thank you for your reply Robin,

And thanks for the welcome.

The part about the visibility is clear. Also the first part about adding a new parameter but i can't get it work. Maybe its because of the fact that i'm new with formula's. Can you add this parameter (in the correct way) in my Family model?. That will help a lot because i'm struggeling with this.

I think i will get the visibility parameters done by myself.

Another way (If you do need to sometimes show only 1 object) is to set the distance between the last to objects to zero (Or as close as possible if that breaks) if the count is less than 2. So visually there is 1 object even though the array is 2.
(Obviously if you are arraying shared families that you want to schedule it will still count 2).

Hi guys,

I think i just did it now . Thanks Robin, it solved my problem. ( And i think i remember you from BSA WDB, i did my internship at the same Company a few years ago).

Yep that's where I used to work about a year ago now. I think I remember your name, but there were a lot of interns during the years, so I'm afraid I don't have a sharp recollection of you :hide:. Send me a message with your info (LinkedIn for example) so we can connect.

Good that you solved it on your own, much better way to learn!

Had not looked at your family before now, looks like you are building scaffolding?

While you're at it, swing over to the Revit Ideas page and upvote this Idea

so we (hopefully) won't have to do these silly workarounds in the future.
THe Idea is "Under Review", so it does have a chance of being worked on if it gets enough votes.

Great Idea I've just voted!!, thank's Dave